How long must a 0.54-mm-diameter aluminum wire be to have a 0.42 A current when connected to the terminals of a 1.5 V flashlight battery

L = 30.85 m

Explanation:

First, we calculate the resistance of the wire by using Ohm's Law:

V = IR

where,

V = Potential Difference = 1.5 V

I = Current = 0.42 A

R = Resistance of Wire = ?

Therefore,

Now, the cross-sectional area of wire will be:

Now, the resistance of the wire is given as:

where,

L = Length of Wire = ?

ρ = resistivity of aluminum = 2.65×10⁻⁸ Ohm.m

Therefore,

L = 30.85 m

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i just did this and got a 100.

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =