A 700 kg car is driving 50 m/s down the interstate. It speeds up to 75 m/s in 8 seconds. What was the force required for the car to accelerate in that
amount of time?

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s