Two objects of mass 5 kg and 8 kg at rest F1 and F2 meters force applied on both the boxes respectively If the speed of both the objects after 5 sec become 16m/s and 15m/s respectively find the value of F1 and F2?

F1 = 16 N and F2 = 24 N

Explanation:

Formula used => F = m×a and v-u= at

So, as we know force = mass × acc.

so acc. of first block = <math> F1/5 </math>. and acc. of second block = <math> F2/ 8 </math> so as v-u= at.. now

Here u= 0 as the objects are placed at rest initially..

thus, v= at

FOR 1ST BLOCK

16= <math> F1/5 </math> × 5 ==> F1 = 16 N

FOR 2ND BLOCK

15= <math> F2/ 8 </math> × 5 ==> F2= 24 N

the answer is b, have negligible mass

this could be newton#'s law of cooling. the cooling curve is exponential