A point charge of 4 µC is located at the center of a sphere with a radius of 25 cm. Find the electric flux through the surface of the sphere. The Coulomb constant is 8.98755 × 109 N · m2 /C 2 and the acceleration due to gravity is 9.8 m/s 2 .Answer in units of N · m2 /C.

Ф = 4.5176x10⁵ N . m² / C

Explanation:

In this case, we need to use two expressions in order to calculate the electric flux of the sphere.

First the Electric flux is calculated using this expression:

Ф = E * A  (1)

Where:

E: Electric field

A: Area of the sphere

To get the electric field E, we use this expression:

E = K * q / r²    (2)

If we replace (2) into (1) we have the following:

Ф = K * q * A / r²    (3)

Finally, we need to know the expression to get the area of a sphere which is the following:

A = 4πr²   (4)

Replacing into (3):}

Ф = K * Q * 4πr² / r²       discarting r²:

Ф = K * Q * 4π   (5)

Now, all we need to do is replace the given values and solve for the electric flux of the sphere:

Ф = 8.98755x10⁹ * 4x10⁻⁶ * 4 * π

Hope this helps

if you answer my question i will answer yours

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2