1. A plane starts from rest and aceelerates in a straight line along the ground before take-off. It
moves 600 m in 12 s. Calculate the distance
moved during the twelfth second.

s=600 m

t=12 s

s=0.5*a*t² (initial speed V0=0)

a=(2*s)/t²

a=(2*600)/12²

a≈8.33 m/s²

L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)

L=0.5*a*(t2²-t1²)

L=0.5*((2*s)/t²)*(t2²-t1²)

L=0.5*((2*600)/12²)*(12²-11²)

L ≈ 95.83 m

it has to be b, about 97 percent.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle