a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br />a. tension in the string<br />b. speed of the body in the circle<br />​

a)  T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

        sin 30 =

        cos 30 =

        Tₓ = T sin 30

        T_y = T cos 30

Y axis  

       T_y -W = 0

       T cos 30 = mg                     (1)

X axis

        Tₓ = m a

they relate it is centripetal

        a = v² / r

we substitute

         T sin 30 = m            (2)

a) we substitute in 1

         T =

         T =

         T = 2.26 N

b) from equation 2

           v² =

If we know the length of the string

          sin 30 = r / L

          r = L sin 30

we substitute

          v² =

          v² =

For the problem let us take L = 1 m

let's calculate

          v =

          v = 1.68 m / s

unlike poles attract

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.