Two girls are pulling on opposite ends of a thick rope. Both girls are pulling on the rope with the same force but in opposite directions. If both girls
continue to pull with the same force, what will MOST likely happen? *
a. One girl will pull the other toward her
b. Both girls will stay in the same place
c. Gravity will cause the rope to sag
d. The rope will break

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j