Now determine the precise time that the cars started their trip (hour:minute:second) if Car 1 passed the streetlight at 12:25:00 and was 25 seconds before Car 2. Hint: Determine how far the cars traveled and then use the known velocity of Car 1 to estimate how much travel time it needed to go that distance.

This question is incomplete, the missing part is in the image below;

the precise time that the cars started their trip is 12:00:00

Explanation:

Given that;

from the image; The velocity of car1 V1 = 1/60 mile/seconds

Given the precise time that the car 1 passed the streetlight ( 12:25:00 )

if car 1 passed 25 seconds before car 2

meaning Car 2 passed the the streetlight at 12:50:00

now time delay is the difference between the two times; i.e

12:50:00 - 12:25:00 = 25 sec

so the distance between starting point and streetlight = 25×1 = 25 miles

Now, time required for Car1 to travel 25 miles distance will be;

t = distance/velocity of car1 = 25 / ( ) = 1500 sec = 25 min

so the precise time that the cars started their trip will be;

12:25:00 - 25 min = 12:00:00

Therefore, the precise time that the cars started their trip is 12:00:00

not really sure but thinking 1.54 mm/us

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: