What is the size of the force acting on a copper wire with a magnetic flux density of 3.6 x 10 2 T acting at right angles to the wire of length 19 m and current of 0.043 A? Round your answer to 2 significant
figures.

2900 N

Explanation:

We are given;

Magnetic flux density; B = 3.6 × 10² T

Length of wire; L = 19 m

Current; I = 0.043 A

Formula for force in this regards is;

F = BIL

Where;

B is Magnetic flux density

I is current

L is length

Thus;

F = 3.6 × 10² × 0.043 × 19

F = 2941.2

To 2 significant figures gives;

F = 2900 N

answer; equivalent to a one(1) horsepower motor;