A rocket is shot from the top of a cliff 300m above sea level with a velocity u at an angle of 45° to the
horizontal.
e
(a) What time does the rocket take to hit a boat after
it has been fired. Take g = 10 ms?
(b) What is the value of 'u' if the rocket hits the boat
4.2km away on the sea.​

One splits the atoms and molecules  the other combines them

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Physical science b final exam bernoulli’smovepowercompound translucent the sun i was having such a pain for this searching every question so i hope i made someone happy