About 50 000 years ago, in an area located outside Flagstaff, Arizona, a giant 4.5 x 107-kg meteor fell and struck the earth, leaving a 180-m-deep hole now
known as Barringer crater. If the meteor was traveling at 20 000 m/s upon
impact, with what average force did the meteor hit the earth?​

F_A =5.625*10^1^6N

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

\triangle E=\frac{1}{2} mv^2 +mgd△E=

2

1

mv

2

+mgd

Having the potential and kinetic energy in place

Mathematically solving for Average forceF_AF

A

\triangle E=F_a*d△E=F

a

∗d

F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}F

A

=

160

1/2∗4.5∗10

7

(20,000)

2

−kg+4.5∗10

7

∗9.81∗160

Therefore Average force F_AF

A

is given by

F_A =5.625*10^1^6N

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

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