3.00 m3 of a fixed mass of a gas at 150 kPa. Calculate the pressure if the volume is reduced to 1.20 m3 at a constant temperature.

P₂ = 375 kPa.

Explanation:

Given that,

Initial volume, V₁ = 3 m³

Initial pressure, P₁ = 150 kPa

Final volume, V₂ = 1.2 m³

We need to find the final pressure.

At constant temperature,

So, the new pressure is 375 kPa.

frequency or wavelenth of em radiation in a vacuum

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west