5 points A car, of mass 1600 kg, is travelling at a speed of 20 m/s when the driver
applies the brakes. The car decelerates at a constant rate and stops. The
braking force used to stop the car and driver was 8000 N. Calculate the
braking distance of the car in m. This is a two step problem, you must
calculate a value and use it to find the final answer.

The braking distance of the car is 40 m

Explanation:

The two steps are;

1) Calculation (finding) of the initial kinetic energy , K.E., of the car

2) Calculation (finding) of the braking distance from the calculated K.E., of the car

The initial Kinetic energy of the car, K.E. = 1/2×m×v²

Where;

m = The mass of the car = 1,600 kg

v = The velocity of the car = 20 m/s

∴ K.E. = 1/2 × 1,600 kg × (20 m/s)² = 320,000 joules

2) The work done in stopping the car, W = The braking force, 'F' × The braking distance, 'd'

∴ W = F × d

Where;

F = The braking force = 8,000 N

d = The braking distance of the car

By energy conservation principle, the work, 'W', that is required to stop the car = The initial kinetic energy of the car, K.E.

∴ W = K.E. = 320,000 joules

Therefore, by substituting the known values for the variables, we have;

320,000 J = 8,000 N × d

∴ d = 320,000 J/(8,000 N) = 40 m

The braking distance of the car, 'd' = 40 m.

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by