Physics, 09.02.2021 01:00, skent1423

g You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball is kicked at 37° from the edge of the building with an initial velocity of 21 m/s and lands 63 meters away from the wall. How tall, in meters, is the building that the child is standing on?

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answered: oscarmasinde44

h = 21.5 m

Explanation:

First of all, we define a pair of coordinate axes along the horizontal and vertical direction, calling x-axis to the horizontal and y-axis to the vertical, with the origin in the point where the ball is kicked.Neglecting air resistance, the only influence on the ball once kicked is due to gravity, so the ball is accelerated by the Earth with a constant value of -9.8 m/s2 (assuming the upward direction as positive).So, we can use the kinematic equation for displacement for the vertical direction, as follows:

$\Delta y = v_{oy}* t -\frac{1}{2}*g*t^{2} (1)$

Since the ball is kicked at an angle of 37º from the edge of the building, at an initial velocity of 21 m/s, we can find the horizontal and vertical initial speeds as follows:

$v_{ox} = v* cos 37 = 21 m/s * cos 37 = 16.8 m/s (2)$

$v_{oy} = v* sin 37 = 21 m/s * sin 37 = 12.6 m/s (3)$

In the horizontal direction, since gravity has no component in this direction, the ball moves at a constant speed, equal to v₀ₓ.Applying the definition of average velocity, since we know the horizontal distance traveled, we can find the total time that the ball was in the air, as follows:

$t = \frac{\Delta x}{v_{ox} } = \frac{63m}{16.8m/s} = 3.75 s (4)$

Replacing (4) and (3) in (1), we can find the total vertical displacement, which is equal to the height of the building, as follows:

$-h = 12.6m/s* 3.75s -\frac{1}{2}*(9.8m/s2)*(3.75s)^{2} = -21.5 m (5)$

⇒ h = -(-21.5m) = 21.5 m

answered: Guest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

answered: Guest

Imma say go with a (:

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g You are walking around your neighborhood and you see a child on top of a roof of a building kick a...