how much energy must be absorbed by water with a mass of 0.5kg in order to raise the tempature from 30c to 65c

62760J

Explanation:

Given parameters:

Mass  = 0.5kg  = 500g

Initial temperature  = 30°C

Final temperature  = 65°C

Unknown:

How much energy is absorbed by the water  = ?

Solution:

To solve this problem, we use the expression below:

  H  = m C Δt

  H =  m  x C x (t₂ - t₁ )

m is the mass

C is the specific heat  = 4.184J/g°C

t₂ is the final temperature

t₁ is the initial temperature

So;

              H  = 500 x 4.184 x (65  - 30) = 62760J