Einstein's equivalence principle says that . Einstein's equivalence principle says that . everyone measures the speed of light to be equivalent someone traveling at 0.9c will age at the same rate as someone at 0.99c all people see themselves at an equivalent distance to the center of the universe the effects of gravity are exactly equivalent to the effects of acceleration

According to the Einstein's equivalence principle, the effects of gravity are exactly equivalent to the effects of acceleration.

Einstein's equivalence principle says that  the effects of gravity are exactly equivalent to the effects of acceleration.

Einstein's equivalence principle states that the the force due to gravity and the force of inertia are similar in the nature and there is no need to distinct them.

Thus Einstein's equivalence principle says that  the effects of gravity are exactly equivalent to the effects of acceleration.

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Einstein's equivalence principle says that .

the effects of gravity are exactly equivalent to the effects of acceleration

Explanation:

The equivalence principle is one of the fundamental laws of physics, as enunciated by Einstein.  It categorically states that the gravitational and inertial forces are of a similar nature.  In physics, a gravitational acceleration is the acceleration of an object in a free fall within a space.  The importance of Einstein's Equivalence Principle is explained by his theory of general relativity.  This theory states that mass is the same, whether inertial or gravitational.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s