Determine the stopping location of the prize wheel . At this moment it is centered on the number 18. It is spinning rate of 160.10 rpm. It’s slowing at a rate of 1.3 rad/s/s. Predict the time the wheel will remain spinning, the angular displacement will go through and then use this to predict the number in which the wheel will stop.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

2b2t

explanation:

2b2t