A 0.17 Kg cue ball is moving at 20 m/s on a pool table and hits a stationary blue ball. After the collision the two bounce off each other and the cue ball keeps moving at 5 m/s. How fast does the blue ball move after being hit? Help

Velocity=total displacement/timefrom house to store is 500 from store to neighbor is 200 therefore total displacement=500+200=700metrestherefore,700metres/910seconds=0.8metres per second

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then