HELP PLEASE PLEASE A 1.50 × 103 kilogram car is traveling east at 20 meters per second. The brakes are applied and the car is brought to rest in 5.00 seconds.
Calculate the magnitude of the impulse applied to the car to bring it to rest.

Calculate the force on the car.

Magnitude of Impulse: 30000 kg · m/s or 30000 N · s

Force on the Car: -6000 N

Math

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Physics

Momentum

Step 1: Define

Mass m = 1.50 × 10³ kg

Velocity v = 20 m/s east

Change in time Δt = 5.00 s

Step 2: Find Magnitude

Step 3: Find Force

We use the Law of Conservation of Momentum to find our break force acting upon the car.

Since the car is deaccelerating, the break force would be towards the west direction (negative as east is our positive direction).

∴ F = -6000 N

| impulse | = 30000 N * s

force = -6000 N

Explanation:

The Impulse-Momentum Theorem states that the impulse applied to an object is equal to the change in momentum of the object. Therefore,

We can use either side of the equation to find the impulse of the object. Since we don't have the force applied to the object, we can use the right side:

We are given the mass of the car and the initial and final velocity. Let's set the right direction to be positive and the left direction to be negative.

Substitute the known values into the equation.

The magnitude of the impulse applied to the car to bring it to rest is |-30000| = 30000 N * s.

We can derive the force from the Impulse-Momentum Theorem by dividing both sides by Δt.

We know the mass of the car, the change in velocity, and the time elapsed.

Substitute the known values into the equation:

The force on the car is -6000 N.

answerscientific theory;