How much force did the puck experience to attain this acceleration? And what is the weight of the puck? Acceleration = 33.2 m/s/s

Useful Information:

F = ma

F sub g = mg where g is 9.8 m/s^2

F sub g means gravitational force

mass of the hockey puck = 169.7 g = 0.1697 kg

mass of the regulation composite hockey stick = 737 g = 0.737 kg

For example, if F = 100 N, T = 0.04 s and m = 0.17 kg, then a = 588 m/s2 and v = 23.5 m/s. Given that the acceleration to to gravity is 9.8 m/s2, the acceleration of a puck is huge by comparison. A higher puck speed will result if the force on the puck is increased or if the force is applied for a longer time.

their crystal patterns have been disrupted by stress

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s