PLEASE HELP❤️❤️❤️❤️ 1. A spring extends by 20 cm when a force of 2 N is applied. What is the value of the spring constant in N/m?
2. A spring extends by 5 cm when a force of 20 N is applied to it. What force would be needed to extend the
spring by 10 cm?

1. 10 N/m

2. 40 N

Explanation:

1. Determination of the spring constant.

We'll begin by converting 20 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m / 100 cm

20 cm = 0.2 m

Finally, we shall determine the spring constant. This can be obtained as follow:

Extention (e) = 0.2 m

Force (F) = 2 N

Spring constant (K) =?

F = Ke

2 = K × 0.2

Divide both side by 0.2

K = 2/0.2

K = 10 N/m

Thus, the spring constant is 10 N/m

2. Determination of the force.

Initial extention (e₁) = 5 cm

Initial force (F₁) = 20 N

Final extension (e₂) = 10 cm

Final force (F₂) =?

F = Ke

Divide both side by e

K = F /e

Therefore,

F₁ /e₁ = F₂/e₂

20/5 = F₂/10

4 = F₂/10

Cross multiply

F₂ = 4 × 10

F₂ = 40 N

Thus, a force of 40 N is needed to stretch the spring by 10 cm.

inverse v=i*r

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