Q12: An electric circuit consists of resistance of 5 ohm and two parallel thick wires at 40 cm distance apart. A metal rod is placed perpendicular to
wires to close the circuit, if the confined area between the wires was
perpendicular to magnetic flux density 0.3T, The force required to move
metal rod to acquire a uniform velocity of 400 cm/min, is:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s