A certain compact disc (CD) contains 783.216 megabytes of digital information. Each byte consists of exactly 8 bits. When played, a CD player reads the CD's information at a constant rate of 1.5 megabits per second. How many minutes does it take the player to read the entire CD? Express your answer using two significant figures

69.62 minutes

Explanation:

From the information we have here,

1 byte is = 8 bits

So 1 megabyte = 8 megabits

Then

783.216 x 8 megabits = 6265.728 megabits

This player has its reading capacity at 1.5 megabits / second

So 1 minute = 60x1.5

= 90 megabits / min

Then we have the entire reading time of this CD player to be =

6265.728/90

= 69.62 minutes.

This answers the question

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.