To test the performance of its tires, a car travels along a perfectly flat (no banking) cir-
cular track of radius 284 m. The car increases
its speed at uniform rate of
at
4.8 m/s?
dt
until the tires start to skid.
If the tires start to skid when the car reaches
a speed of 39.6 m/s, what is the coefficient of
static friction between the tires and the road?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

A,d, and e on edgunuity

You need to calculate the string in between two masses