- An object in equilibrium has three forces exerted on it. A 33-N force act at 90° from the x-axis and a 44-N force act at 60°. What are the magnitude and direction of the third force

The magnitude and direction of the third force is;

F3 = 74.44 N

θ3 = 72.81° in the south direction

We are given;

F1 = 33 N

F2 = 44 N

θ1 = 90°

θ2 = 60°

Let the third force be F3 which will serve as the resultant

Let's first find the x and y component of the forces.

F1x = F1 cos θ1

F1x = 33 × cos 90

F1x = 0 N

F1y = F1 sin θ1

F1y = 33 × sin 90

F1y = 33 N

F2x = F2 cos θ2

F2x = 44 × cos 60

F2x = 22 N

F2y = F2 sin θ2

F2y = 44 × sin 60

F2y = 38.11 N

Thus, the resultant of the x component is;

F3x = F1x + F2x

F3x = 0 + 22

F3x = 22 N

The resultant of the y component is;

F3y = F1y + F2y

F3y = 33 + 38.11

F3y = 71.11 N

Thus, magnitude of resultant of the F3 force is;

F3 = √((F3x)² + (F3y)²)

F3 = √(22² + 71.11²)

F3 = 74.44 N

The direction of the resultant of F3 is;

θ3 = tan^(-1) F3y/F3x

θ3 = tan^(-1) 71.11/22

θ3 = 72.81° in the south direction

Read more about resultant of forces at;

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The magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

Explanation:

Let F1, F2 and F3 are three forces exerted on an object.

We have to find the direction and magnitude of third force i.e F3.

Now,

x-component of  resultant

y-component of resultant

South

Hence, the magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

c

explanation:

i believe the answer is c and this is only worth 10 points you might wanna change it

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: