A satellite is in orbit 3.110106 m from the center of Earth. The mass of Earth is 5.98011024 kg Calculate the orbital period of the satellite.

9194.4278 seconds

Explanation:

Orbital period is given by :

T² = (4π²r³) /GM

G = Gravitational constant = 6.67 * 10^-11

M = 5.9801 * 10^24 kg

r = (3.110 * 10^6 m + 6378000 m) =3110000 + 6378000 = 9488000 m

T² = (4π² * 9488000^3) / (6.67* 10^-11 * 5.9801*10^24)

T² = 3.37197 * 10^22 / 398872670000000

T² = 84537504.161415

T = sqrt(84537504.161415)

T = 9194.4278 seconds

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.