A car accelerates from rest in a straight line. During the first 14s, the acceleration is uniform and the car reaches the speed of 25m/s. Calculate the acceleration of the car.

v = u + at

25 = 0 + a(14)

a(14) = 25

a = 25/14

a = 1.71 (3sf)

explanation:

u use the equation of motions

v = u + at

v is final velocity, aka 25

u is initial velocity, which is 0 as it was initially at rest

t is time, which is 14s

then u sub in the values and calculate a

i think it is non rem sleep

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