Find the period of a pendulum that has a length of .6m and is on earth. Make sure that you show your work and prominently display the equation that you use to solve it.

The period of this pendulum is

Explanation:

The equation of motion of a pendulum is given by:

(1)

Where:

θ is the angle of motion

g is the gravity at the earth surface (9.81 m/s²)

L is the length of the pendulum (0.6 m)

Now, using equation (1) we can find the square angular frequency (ω), it will be:

Let's recall that the angular frequency is , then the period will be:

Therefore, the period of this pendulum is

I hope it helps you!

answer///isobars;

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.