A concrete block with a mass of was dropped from the top of a building. The ground exerted an impulse of 120 Newton-meters on the block when the block hit the ground . What was magnitude of the block's change in momentum at the moment it hit the ground ?

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

v=ir = 3x15 =45 v

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

answer; how far out of place which the object finished relative to the starting location;