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A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
1. Calculate the impulse delivered to the ball.
2. What was the change in momentum of the ball?
3. What was the velocity of the ball as it left the tennis racket?
4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s?
Answers: 1
Physics, 22.06.2019 13:20, monkeygaming274
Ahanging spring stretches by 35.0 cm when an object of mass 450 g is hung on it at rest. in this situation, we define its position as x = 0. the object is pulled down an additional 18.0 cm and released from rest to oscillate without friction. what is its position x at a moment 84.4 s later? express your answer in cm.
Answers: 1
Physics, 22.06.2019 14:30, lizzie3545
Aweight lifter raises a 1600 n barbell to a height of 2.0 meters. how much work was done? w = fd a) 30 joules b) 3000 joules c) 320 joules d) 3200 joules
Answers: 2
Please I really need help, I will mark you brainliest
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