An iron bolt is used to connect two iron plates together. the bolt must withstand shear forces up to about 3000 n. calculate the minimum diameter for the bolt, based on a safety factor of 6.3.

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Shear strength of steel 
= 0.75 * 800 * 10^6 N/m2 

total load with safety factor 
= 3000 * 5.6 
= 16800 N 

Cross section area needed 
= 16800 / 0.75 * 800 * 10^6 

= 28 * 10^(-6) m2 

Diameter of bolt 
= square root of [ 4 * area / phi} 

= sq root [ 35.65 10^ -6] 

= 5.97 * 10^ -3 m 

= 5.97 mm

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