Calculate the magnitude of the following vector components in OX and OY directions

Very easy question

For x-component, we use Fₓ = Fcosα

For y-component, we use Fy = Fsinα

The major problem is with angle α.

Here α = 90+30

Because the angle is measured from +ve X-axis.

By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.

So for further calculation,

Fₓ = Fcos(90+30) = 25(-sin30)

Fₓ = -25(1/2) = 25/2 = 12.5  - will be eliminate because force in magnitude is not "-ve"

As it is

Fy = Fsin(90+30) = Fcos30

Fy = 25 (√3 /2) = 25√3/2

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

iron would move it is magnetic there is a mag field around the current in the wire