A pendulum with a mass of 1 kg is released from a height of 1.5 cm above the height of its resting position. How fast will the pendulum be moving when it passes through the lowest point of its swing?

v = 0.54 m/s

Explanation:

The Principle Of Conservation Of Mechanical Energy

In the absence of friction, the total mechanical energy is conserved. That means that

Em=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

When the mass (m=1 kg) of the pendulum is at the top of the path at a height of h=1.5 cm=0.015 m, its kinetic energy is 0 and its potential energy is:

U=1 * 9.8 * 0.015 = 0.147 J

That potential energy is completely transformed into kinetic energy at the bottom of the swing. The speed can be calculated by solving for v:

Multiplying by 2 and dividing by m:

v = 0.54 m/s

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