if a ball is thrown up from the ground and takes 2.30 seconds before it hits the ground. A) what was its initial velocity b) what was its max velocity

A) The initial velocity is 11.27 m/s

B) The maximum velocity is 11.27 m/s

Explanation:

A) The question is with regards to kinematic motion under gravity

The the time it takes the ball to travel up and return back to the ground = 2.30 seconds

Therefore, from the kinematic equation of motion of the ball, under gravity, v = u - g·t, we have;

t = (v - u)/g

Where;

t = The total time of the motion of the ball = 2.30 seconds

v = The final velocity of the ball = 0 m/as at the maximum height

u = The initial velocity of the ball

g = The acceleration due to gravity = 9.8 m/s²

Therefore, given that we have;

The time it takes the ball to ascend = The time it takes the ball to descend

The time it takes the ball to ascend to maximum height = 2.30 second/2 = 1.15 seconds

Substituting the parameter values of the motion to maximum height, we get;

1.15 = (0 - u)/(-9.8)

-9.8 × 1.15 = -u

11.27 = u

The initial velocity, u = 11.27 m/s

B) Given that the ball experiences a deceleration on the way up, and that the motion of a parabola is symmetrical about the vertex, which is the maximum height, where the velocity is zero, we have that the initial velocity is equal to the final velocity which are both equal to the maximum velocity

Therefore, the initial velocity = The maximum velocity = 11.27 m/s.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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