58) Two balls, A and B are simultaneously projected from the top of a building at 10 mis upwards & 20 m/s downwards respectively. Find
out the separation btwn them 3 sec after projection.

90 m

Explanation:

For ball A::

The equation of a ball moving upwards is given by the formula:

s = ut - (1/2)gt²

where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) - (1/2) * 10 * 3²

s = 30 - 45

s = -15 m

The negative sign means the object travels in the opposite direction. Hence s = 15 m

For ball B::

The equation of a ball falling downwards is given by the formula:

s = ut + (1/2)gt²

Given that:

u = 10 m/s, t = 3 sec, g = 10 m/s², hence:

s = (10 * 3) + (1/2) * 10 * 3²

s = 30 + 45

s = 75 m

Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.