While driving his sports car at 20.00 m/s down a four lane highway, a man comes up behind a very slow school bus. The man is in a hurry so he
decides to pass the bus. If the man's car can accelerate at 6.00 m/s^2,
how long will it take for him to reach a speed of 35.00 m/s in order to pass
the bus? Round to the nearest hundredth. (2 decimal places) Type the
number only.

2.50 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 20 m/s

Acceleration (a) = 6 m/s²

Final velocity (v) = 35 m/s

Time (t) =?

Thus, we can obtain the time taken for the man to reach a speed of 35 m/s as follow:

v = u + at

35 = 20 + 6t

Collect like terms

35 – 20 = 6t

15 = 6t

Divide both side by 6

t = 15/6

t = 2.50 s

Thus, it will take the man 2.50 s to reach a speed of 35 m/s.

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation: