Physics, 18.01.2021 18:10, sk9600930

A pot with a steel bottom 8.50 mm thick rests on a hot stove. The area of the bottom of the pot is 0.150 m2. The water inside the pot is at 100.0o C, and 0.390 kg are evaporated every 3.00 min. Find the temperature of the lower surface of the pot, which is in contact with the stove.

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answered: kiki197701

The temperature of the lower surface of the pot is 105.5397 $\overline 3$ °C

Explanation:

The given parameters are;

The thickness of the pot with steel bottom = 8.50 mm = 0.0085 m

The area of the bottom of the pot = 0.150 m²

The temperature of the water inside the pot, T₁ = 100.0 °C = 373.15 K

The mass of the water inside the pot evaporated every 3.00 min = 0.390 kg

The latent heat of vaporization of water, L = 2,256 × 10³ J/kg

The energy transferred per 3 minutes = 2,256 × 10³ × 0.390 = 879,840 J

The heat transferred per second, Q = 879,840 J/(3.00 × 60s) = 4888 Watts

The thermal conductivity of steel, K = 50.2 W/(m·K)

Therefore, the energy transferred is given as follows;

$K = \dfrac{Q \cdot d}{A \cdot \Delta T}$

Where;

K = The thermal conductivity = 50.2 W/(m·K)

Q = The heat transferred = 4888 W

d = The distance between two isothermal planes = 0.0085 m

A = The surface area of the heat transfer = 0.150 m²

ΔT = The temperature difference between two isothermal planes = T₂ - T₁

T₂ = The temperature of the lower surface of the pot

$50 \ W/(m\cdot K) = \dfrac{4,888 \ W \times 0.0085 \ m}{0.15 \ m^2 \times \Delta T}$

$\Delta T = \dfrac{4,888 \ W \times 0.0085 \ m}{0.15 \ m^2 \times 50 \ W/(m\cdot K)} = 5 \dfrac{1012}{1875} \ K = 5.5397 \overline 3 \ K$

ΔT = T₂ - T₁

Therefore, T₂ = T₁ + ΔT

T₂ = 373.15 K + 5.5397 $\overline 3$ K = 378.6897 K

T₂ = 378.689 $\overline 3$ K = (378.689 $\overline 3$ - 273.15)°C = 105.5397 $\overline 3$ °C

The temperature of the lower surface of the pot = T₂ = 105.5397 $\overline 3$ °C.

answered: Guest

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

answered: Guest

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

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A pot with a steel bottom 8.50 mm thick rests on a hot stove. The area of the bottom of the pot is 0...