Physics, 17.01.2021 16:00, destinyleisantos
Starting from rest, a sprinter reaches his top velocity in 3 seconds. He runs a distance of 24m in 3 seconds. What is his acceleration? (Assume his acceleration is uniform)
Answers: 3
Time taken; 
Distance covered; 
![24m = [0 * 3s] + [\frac{1}{2} * a * (3s)^2]\\\\24m = \frac{1}{2} * a * 9s^2\\\\24m = a * 4.5s^2\\\\a = \frac{24m}{4.5s^2} \\\\a = 5.33m/s^2](/tpl/images/1042/3674/a4884.png)
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Starting from rest, a sprinter reaches his top velocity in 3 seconds. He runs a distance of 24m in 3...
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