A car's engine provides a driving force of 30N. The car travels at a steady speed of 20m/s. What is the size of the resistive force acting against the driving force?

30 N

Explanation:

Since the car travels at a steady speed of 20m/s and has a driving force of 30N, there is no net acceleration and thus, the resistive force is also 30 N in magnitude but in the opposite direction to the driving force. This is shown below.

F - f = f' where F = driving force = 30 N. f = resistive force and f'= net force.

f' = 0 since there is no acceleration. So,

F - f = 0

F = f = 30 N

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft