HELP PLS Ideal gas pressure increases 10 times, but absolute temperature decreases 14 times. How much times does the volume of gas changes if its mass does not change?

Explanation:

The formula to be used here is that of the general gas law which is below

P₁V₁/T₁ = P₂V₂/T₂

where P₁ is the initial pressure (and can be represented as 1 atm)

V₁ is the initial volume (and can be represented as 1 cm³)

T₁ is the initial temperature (and can be represented as 1 °C = 274K)

P₂ is the final pressure (and would be 10 atm since the pressure increased 10 times)

T₂ is the final temperature (and would be 0.07°C = 273.07K since the temperature decreased 14 times; 1/14 = 0.07)

V₂ is the final volume which is unknown

Using the formula stated earlier

1 × 1/274 = 10 × V₂/273.07

1 × 1 × 273.07 = 10 × V₂ × 274

V₂ = 273.07/2740

V₂ = 0.099 ⇔ 0.1

Thus V₁:V₂ is 1:0.1

This means the volume of gas reduced 10 times (1/10) the original volume

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