A championship weight lifter did 1.10x104of work on a set of barbells weighing
3680 N. How much gravitational potential energy did the barbells have at the maximum
height of the lift? Show your work.

The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units

Where;

h = The maximum height to which he lifts the barbells

Explanation:

The given parameters are;

The  amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units

The weight of the barbells lifted by the championship lifter, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s²

h = The maximum height to which the barbells are lifted by the championship weight lifter

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.

∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units

c. magnitude and direction