What is momentum of 1.5 kg boulder dropped from a cliff after 3.0 s

Given :

Mass of object, m = 1.5 kg.

To Find :

The momentum of boulder dropped from a cliff after 3 seconds.

Solution :

Speed of boulder after 3 seconds of free fall is given by :

v = u + gt       ( Equation of motion )

v = 0 + 10×3    ( g = acceleration due to gravity )

v = 30 m/s

Now, momentum is given by :

P = m × v

P = 1.5 kg × 30 m/s

P = 45 kg m/s

Therefore, momentum of boulder is 45 kg m/s.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.