Suppose the driver of a vehicle applies the brakes while traveling at 8.25 m/s and the car stops after traveling 24.0 m. What was the car's acceleration?

Explanation:

u = 8.25m/s

v = 0.00m/s

s = 24.0m

Using Kinematics, we have v² = u² + 2as.

=> a = (v² - u²) / 2s

= [(0)² - (8.25)²] / 2(24) = -1.42m/s². (3s.f.)

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day