Two positive charges 12×10^-6C and 8×10^-6 are 10cm apart. Find the workdone in bringing them 4cm together

W = 5.76 J

Explanation:

Given that,

Charge 1,

Charge 2,

The distance between charges is 10 cm.

Initial distance = 10 cm = 0.1 m

Final distance = 10 cm - 4 cm = 6 cm = 0.06 m

We need to find the work done in bringing the 4 cm together.

We know that,

Work done = change in kinetic energy

So, the required work done is 5.76 J.

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~