A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electric field created by the sphere at a point P outside the sphere.

The electric field outside the sphere will be .

Explanation:

Given that,

Radius of solid sphere = R

Charge = q

According to figure,

Suppose r is the distance between the point P and center of sphere.

If be the volume charge density,

Then, the charge will be,

.....(I)

Consider a Gaussian surface of radius r.

We need to calculate the electric field outside the sphere

Using formula of electric field

Put the value from equation (I)

Hence, The electric field outside the sphere will be .

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