At terminal velocity what will be relationship between drag force and driving force

The answer to this question is given below in this explanation section.

Explanation:

                "relationship between drag force and driving force"

The velocity at any time during the flight depends on the corresponding acceleration of the vehicle and the balance of forces acting of the vehicle.Forces acceleration and velocity are all vector quantities having both a magnitude and a direction.When describing the motion of an object caused by forces,one must account for both the magnitude and direction.The forces present during coasting flights are the drag and the weight.The weight is constant is magnitude and is always directed toward the center of earth.The magnitude of the drag change the square of the velocity.During ascent the drag is in the same direction as the weight .But during descent the drag opposes the weight.

For the descending rocket the next vertical external force  F is equal to the difference between the drag D and the weight W:

                  F=D-W

The impetus power or energy behind something in motion,as in he was clearly the driving force in the new administration This term transfer the force that sets in motion an engine or vehicle to other enterprises.Gravity is the driving force for an object falling towards the ground.

A skate boarder relies on the ground pushing on the sole of her shoe  to drive her skateboard along.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz