Caris parked on road slopes upward at angle θ. The magnitude the force of the road on the is mg cosθ. Is the magnitude of the stalie friction force on the less equal to or greater than μ2mgcosθ? Explain.

fr = μ m g cos θ

the correct answer is less than fr = μ 2m g cos θ

Explanation:

Let's propose the solution of the problem to be able to answer the question, let's fix a reference system with one axis parallel to the plane (x-axis) and the other perpendicular, let's write Newton's second law

Y Axis  

     N - W cos θ = 0

     N = mg cos θ

X axis.

     fr - w sin θ = 0

     fr = mg sin θ

the friction force is described by the expression

     fr = μ N

      fr = μ m g cos θ

When we analyze this expression we see that the friction force is equal to (μ_k m g cos θ)

If everything is well written in your problem, the correct answer is less, even though I think you have an error when writing the number

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

it is the second option.