A car accident my rolls off a cliff as it leaves the cliff it has a horizontal velocity of 13 ms it hiys the ground 60 m from the shoreline calculate the height of the cliff

104.59 m

Explanation:

The following data were obtained from the question:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Height (h) =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Time (t) =?

s = ut

60 = 13 × t

Divide both side by 13

t = 60 / 13

t = 4.62 s

Finally, we shall determine the height cliff. This can be obtained as follow:

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4.62²

h = 4.9 × 21.3444

h = 104.59 m

Thus, the height of the cliff is 104.59 m