A bus starts to move from rest. If it is accelerated by 0.8m/s2, calculate the velocity and distance traveled after 8 s.

We are given:

Initial velocity (u) = 0 m/s

acceleration (a) = 0.8 m/s²

time interval (t) = 8 seconds

final velocity (v) = v m/s

distance travelled (s) = s m

Solving for the final velocity:

We know that:

v = u + at                                [first equation of motion]

v = 0 + (0.8)(8)                       [replacing the variables]

v = 6.4 m/s

Hence, the final velocity is 6.4 m/s

Solving for the distance travelled:

We know that:

s = ut + 1/2(at²)                     [second equation of motion]

s = (0)(8) + 1/2(0.8)(8)(8)      [replacing the variables]

s = 1/2(6.4*8)

s = 25.6 m

Hence, the distance travelled is 25.6 m

the first, second, and fifth options

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.