A student heated 50mL of water from zero degree Celsius to 60 degree Celsius. How much energy did she use to heat the water? Remember cal = m x delta T

Q = 12.5 kJ

Explanation:

Given that,

Mass of water, m = 50 mL = 0.05 kg

The temperature changes from 0 degree Celsius to 60 degree Celsius.

We need to find how much energy she use to heat the water. The energy required to heat the water is given by :

Where c is specific heat of water, c = 4186 J/kgºC

or

Q = 12.5 kJ

So, the energy used to heat th water is 12.5 kJ.

a.   mass number from atomic number

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j